0=5t^2-2t+0,2

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Solution for 0=5t^2-2t+0,2 equation: 



0=5t^2-2t+0.2

We move all terms to the left:

0-(5t^2-2t+0.2)=0

We add all the numbers together, and all the variables

-(5t^2-2t+0.2)=0

We get rid of parentheses

-5t^2+2t-0.2=0

a = -5; b = 2; c = -0.2;
Δ = b2-4ac
Δ = 22-4·(-5)·(-0.2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-2}{-10}=1/5$

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